49x^2-136x=7x^2-64

Solution for 49x^2-136x=7x^2-64 equation:

49x^2-136x=7x^2-64

We move all terms to the left:

49x^2-136x-(7x^2-64)=0

We get rid of parentheses

49x^2-7x^2-136x+64=0

We add all the numbers together, and all the variables

42x^2-136x+64=0

a = 42; b = -136; c = +64;
Δ = b2-4ac
Δ = -1362-4·42·64
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-136)-88}{2*42}=\frac{48}{84}
=4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-136)+88}{2*42}=\frac{224}{84}
=2+2/3
$